What is the extreme f(x)=(x^2+8x-20)/(x-6) ?

The extreme f(x)=(x^2+8x-20)/(x-6) is Maximum(-2,4),Minimum(14,36)

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extreme f(x)=(x^2+8x-20)/(x-6)

extreme points

f (x) = \frac{x ^{2} + 8 x - 20}{x - 6}

Maximum (- 2, 4), Minimum (14, 36)

Solution steps

f^{'} (x) = \frac{x ^{2} - 12 x - 28}{( x - 6 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 6,

Decreasing

: 6 < x < 14,

Increasing

: 14 < x < \infty

Plug

x = - 2

into

\frac{x ^{2} + 8 x - 20}{x - 6} : 4

Maximum (- 2, 4)

Plug

x = 14

into

\frac{x ^{2} + 8 x - 20}{x - 6} : 36

Minimum (14, 36)

Maximum (- 2, 4), Minimum (14, 36)

f (x) = x + 4 y

f (x, y) = x^{2} + 2 x y + 3 y^{2}

f (x) = \frac{1}{2} I n (\frac{1 + x}{1 - 1})

f (x) = 2 x^{3} - 3 x y + 3 y^{3}

y = 2 x^{3} - 9 x^{2} + 12 x + 2

What is the extreme f(x)=(x^2+8x-20)/(x-6) ?
The extreme f(x)=(x^2+8x-20)/(x-6) is Maximum(-2,4),Minimum(14,36)