What is the extreme y=2x^3-9x^2+12x+2 ?

The extreme y=2x^3-9x^2+12x+2 is Maximum(1,7),Minimum(2,6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme y=2x^3-9x^2+12x+2

extreme points

y = 2 x^{3} - 9 x^{2} + 12 x + 2

Maximum (1, 7), Minimum (2, 6)

Solution steps

f^{'} (x) = 6 x^{2} - 18 x + 12

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 1

into

2 x^{3} - 9 x^{2} + 12 x + 2 : 7

Maximum (1, 7)

Plug

x = 2

into

2 x^{3} - 9 x^{2} + 12 x + 2 : 6

Minimum (2, 6)

Maximum (1, 7), Minimum (2, 6)

f (x) = x^{4} - 50 x^{2} + 9

f (x) = - 4 x^{2} + 8 x - 2, 0 \leq x \leq 3

f (x) = 2 x^{3} - 12 x^{2}

f (x, y) = x^{3} - 3 x + y^{3} + \frac{5}{2} y^{2} - 2 y

f (x) = sin (x) cos (x), 0 \leq x \leq π

What is the extreme y=2x^3-9x^2+12x+2 ?
The extreme y=2x^3-9x^2+12x+2 is Maximum(1,7),Minimum(2,6)