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Popular >

extreme f(x)=3x^2+2x+1

Solution

extreme points

f (x) = 3 x^{2} + 2 x + 1

Solution

Minimum (- \frac{1}{3}, \frac{2}{3})

Solution steps

f^{'} (x) = 6 x + 2

Find intervals:

Decreasing

: - \infty < x < - \frac{1}{3},

Increasing

: - \frac{1}{3} < x < \infty

Plug

x = - \frac{1}{3}

into

3 x^{2} + 2 x + 1 : \frac{2}{3}

Minimum (- \frac{1}{3}, \frac{2}{3})

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=3x^2+2x+1 ?
The extreme f(x)=3x^2+2x+1 is Minimum(-1/3 , 2/3)