What is the extreme f(x)=(ln(x))/(x^4) ?

The extreme f(x)=(ln(x))/(x^4) is Maximum(\sqrt[4]{e}, 1/(4e))

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extreme f(x)=(ln(x))/(x^4)

extreme points

f (x) = \frac{ln ( x )}{x ^{4}}

Solution steps

f^{'} (x) = \frac{1 - 4 ln ( x )}{x ^{5}}

Find intervals:

Increasing

Decreasing

Plug

into

\frac{ln ( x )}{x ^{4}} : \frac{1}{4 e}

\frac{2 x ^{2}}{x ^{2} - 9}

x^{3} ln (x)

f (x) = x^{3} - 6 x^{2} - 15 x + 1

\frac{4 x ^{2}}{x ^{2} - 4}

f (x) = 2 x^{3} - 4 x^{2} - x

What is the extreme f(x)=(ln(x))/(x^4) ?
The extreme f(x)=(ln(x))/(x^4) is Maximum(\sqrt[4]{e}, 1/(4e))