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Popular >

extreme (2x^2)/(x^2-9)

Solution

extreme points

\frac{2 x ^{2}}{x ^{2} - 9}

Solution

Maximum (0, 0)

Solution steps

f^{'} (x) = - \frac{36 x}{( x ^{2} - 9 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 3,

Increasing

: - 3 < x < 0,

Decreasing

: 0 < x < 3,

Decreasing

: 3 < x < \infty

Plug

x = 0

into

\frac{2 x ^{2}}{x ^{2} - 9} : 0

Maximum (0, 0)

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Frequently Asked Questions (FAQ)

What is the extreme (2x^2)/(x^2-9) ?
The extreme (2x^2)/(x^2-9) is Maximum(0,0)