What is the extreme f(x,y)=6xy-x^3-3y^2 ?

The extreme f(x,y)=6xy-x^3-3y^2 is Saddle(0,0),Maximum(2,2)

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extreme f(x,y)=6xy-x^3-3y^2

extreme points

f (x, y) = 6 x y - x^{3} - 3 y^{2}

Saddle (0, 0), Maximum (2, 2)

Solution steps

Find the critical points:

(0, 0), (2, 2)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 6

D (x, y) = 36 x - 36

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Check critical point

(2, 2) :

Maximum

Saddle (0, 0), Maximum (2, 2)

f (x) = 8 y^{2} + 5 x^{2} - 10 y + 6 x - 10

f (x) = 2 x^{3} - 3 x^{2} - 12 x - 1

f (x, y) = x^{3} + y^{2} + \frac{3}{2} x^{2} - 6 x - 4 y + 3

f (x) = 2 x^{3} + 3 x^{2} - 36 x + 5

f (x, y) = (x^{2} + y^{2}) e^{y^{2} - x^{2}}

What is the extreme f(x,y)=6xy-x^3-3y^2 ?
The extreme f(x,y)=6xy-x^3-3y^2 is Saddle(0,0),Maximum(2,2)