What is the extreme 2x^3-3x^2-36x+5 ?

The extreme 2x^3-3x^2-36x+5 is Maximum(-2,49),Minimum(3,-76)

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extreme 2x^3-3x^2-36x+5

extreme points

2 x^{3} - 3 x^{2} - 36 x + 5

Maximum (- 2, 49), Minimum (3, - 76)

Solution steps

f^{'} (x) = 6 x^{2} - 6 x - 36

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 2

into

2 x^{3} - 3 x^{2} - 36 x + 5 : 49

Maximum (- 2, 49)

Plug

x = 3

into

2 x^{3} - 3 x^{2} - 36 x + 5 : - 76

Minimum (3, - 76)

Maximum (- 2, 49), Minimum (3, - 76)

6 x^{2} - 2 x^{3} + 3 y^{2} + 6 x y

f (x, y) = 2 x^{3} y^{2} + 4 x y + 6

K (r, s) = 2 r - s

f (x) = x^{5} - 10 x^{4} + 25 x^{3}

1 + 6 x^{2} - x^{3}

What is the extreme 2x^3-3x^2-36x+5 ?
The extreme 2x^3-3x^2-36x+5 is Maximum(-2,49),Minimum(3,-76)