What is the extreme f(x)=6xy-x^3-3y^2 ?

The extreme f(x)=6xy-x^3-3y^2 is Saddle(0,0),Maximum(2,2)

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extreme f(x)=6xy-x^3-3y^2

extreme points

f (x) = 6 x y - x^{3} - 3 y^{2}

Saddle (0, 0), Maximum (2, 2)

Solution steps

Find the critical points:

(0, 0), (2, 2)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 6

D (x, y) = 36 x - 36

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Check critical point

(2, 2) :

Maximum

Saddle (0, 0), Maximum (2, 2)

f (x, y) = 2 x^{2} + x y^{2} - 6 x y + 5 x + 2

f (x) = x 36 - x^{2}

f (x) = x^{4} + \frac{4 x ^{3}}{3} - 4 x^{2}

f (x) = 3 y^{2} - 2 y^{3} - 3 x^{2} + 6 x y

f (x) = 3 x^{3} - 6 x^{2} - 5 x + 1

What is the extreme f(x)=6xy-x^3-3y^2 ?
The extreme f(x)=6xy-x^3-3y^2 is Saddle(0,0),Maximum(2,2)