What is the extreme f(x)=x^3-12x^2+45x+8 ?

The extreme f(x)=x^3-12x^2+45x+8 is Maximum(3,62),Minimum(5,58)

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extreme f(x)=x^3-12x^2+45x+8

extreme points

f (x) = x^{3} - 12 x^{2} + 45 x + 8

Maximum (3, 62), Minimum (5, 58)

Solution steps

f^{'} (x) = 3 x^{2} - 24 x + 45

Find intervals:

Increasing

: - \infty < x < 3,

Decreasing

: 3 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = 3

into

x^{3} - 12 x^{2} + 45 x + 8 : 62

Maximum (3, 62)

Plug

x = 5

into

x^{3} - 12 x^{2} + 45 x + 8 : 58

Minimum (5, 58)

Maximum (3, 62), Minimum (5, 58)

f (x) = \frac{x}{x ^{2} - x + 4}

z (b, v) = b^{2 v}

f (x) = x^{2} - x - 1

f (x) = 2 x^{2} - 5 x + 3

f (x) = 9 x^{2} - 4

What is the extreme f(x)=x^3-12x^2+45x+8 ?
The extreme f(x)=x^3-12x^2+45x+8 is Maximum(3,62),Minimum(5,58)