What is the extreme f(x)=x^5-5x^4+1 ?

The extreme f(x)=x^5-5x^4+1 is Maximum(0,1),Minimum(4,-255)

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extreme f(x)=x^5-5x^4+1

extreme points

f (x) = x^{5} - 5 x^{4} + 1

Maximum (0, 1), Minimum (4, - 255)

Solution steps

f^{'} (x) = 5 x^{4} - 20 x^{3}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 0

into

x^{5} - 5 x^{4} + 1 : 1

Maximum (0, 1)

Plug

x = 4

into

x^{5} - 5 x^{4} + 1 : - 255

Minimum (4, - 255)

Maximum (0, 1), Minimum (4, - 255)

f (x) = x^{3} - 9 x^{2} + 15 x + 4

f (x, y) = Z = x^{2} - 3 x y + 2 y^{2} - 4 y

f (x, y) = x^{3} + y^{3} - 3 x^{2} - 3 y + 10

2 t^{4} + 6 t^{3} - 5

f (x, y) = arcsec (x^{2} - ∣ y ∣)

What is the extreme f(x)=x^5-5x^4+1 ?
The extreme f(x)=x^5-5x^4+1 is Maximum(0,1),Minimum(4,-255)