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Popular >

extreme f(x)=x^2+6x-3

Solution

extreme points

f (x) = x^{2} + 6 x - 3

Solution

Minimum (- 3, - 12)

Solution steps

f^{'} (x) = 2 x + 6

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < \infty

Plug

x = - 3

into

x^{2} + 6 x - 3 : - 12

Minimum (- 3, - 12)

Popular Examples

extreme f(x)=x^3-9x^2+1 extreme points

f (x) = x^{3} - 9 x^{2} + 1

extreme f(x)=x^3-3 extreme points

f (x) = x^{3} - 3

extreme f(x,y)=3x^3+y^2-9x+4y extreme points

f (x, y) = 3 x^{3} + y^{2} - 9 x + 4 y

extreme f(x)=(x^2-4)^3 extreme points

f (x) = (x^{2} - 4)^{3}

extreme f(x,y)=sqrt(6-(x^2)/3-(y^2)/2)extreme points

f (x, y) = 6 - \frac{x ^{2}}{3} - \frac{y ^{2}}{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+6x-3 ?
The extreme f(x)=x^2+6x-3 is Minimum(-3,-12)