What is the extreme f(x)=x^3-9x^2+1 ?

The extreme f(x)=x^3-9x^2+1 is Maximum(0,1),Minimum(6,-107)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3-9x^2+1

extreme points

f (x) = x^{3} - 9 x^{2} + 1

Maximum (0, 1), Minimum (6, - 107)

Solution steps

f^{'} (x) = 3 x^{2} - 18 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 0

into

x^{3} - 9 x^{2} + 1 : 1

Maximum (0, 1)

Plug

x = 6

into

x^{3} - 9 x^{2} + 1 : - 107

Minimum (6, - 107)

Maximum (0, 1), Minimum (6, - 107)

f (x) = x^{3} - 3

f (x, y) = 3 x^{3} + y^{2} - 9 x + 4 y

f (x) = (x^{2} - 4)^{3}

f (x, y) = 6 - \frac{x ^{2}}{3} - \frac{y ^{2}}{2}

f (x) = x^{8} ln (x)

What is the extreme f(x)=x^3-9x^2+1 ?
The extreme f(x)=x^3-9x^2+1 is Maximum(0,1),Minimum(6,-107)