What is the extreme f(x)=x^8ln(x) ?

The extreme f(x)=x^8ln(x) is Minimum(1/(\sqrt[8]{e)},-1/(8e))

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extreme f(x)=x^8ln(x)

extreme points

f (x) = x^{8} ln (x)

Solution steps

f^{'} (x) = 8 x^{7} ln (x) + x^{7}

Find intervals:

Decreasing

Increasing

Plug

into

x^{8} ln (x) : - \frac{1}{8 e}

f (x) = 2 x^{3} + 4 x^{2}

f (x) = ln (x^{2} + 2)

- lo g_{5} (x)

8 x^{2} + 14 x y + 3 y^{2} + 10 x - 4

f (x) = 6 x^{2} + 6 x - 12

What is the extreme f(x)=x^8ln(x) ?
The extreme f(x)=x^8ln(x) is Minimum(1/(\sqrt[8]{e)},-1/(8e))