en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=ln(x^2+2)

Solution

extreme points

f (x) = ln (x^{2} + 2)

Solution

Minimum (0, ln (2))

Solution steps

f^{'} (x) = \frac{2 x}{x ^{2} + 2}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

ln (x^{2} + 2) : ln (2)

Minimum (0, ln (2))

Popular Examples

extreme-log_{5}(x)extreme points

- lo g_{5} (x)

extreme 8x^2+14xy+3y^2+10x-4 extreme points

8 x^{2} + 14 x y + 3 y^{2} + 10 x - 4

extreme f(x)=6x^2+6x-12 extreme points

f (x) = 6 x^{2} + 6 x - 12

extreme f(x,y)=x^3-2xy+y^2+4 extreme points

f (x, y) = x^{3} - 2 x y + y^{2} + 4

extreme f(x)=(x^2+1)/(x^2-4x+4)extreme points

f (x) = \frac{x ^{2} + 1}{x ^{2} - 4 x + 4}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=ln(x^2+2) ?
The extreme f(x)=ln(x^2+2) is Minimum(0,ln(2))