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Popular >

extreme f(x)=x^2+2x+4

Solution

extreme points

f (x) = x^{2} + 2 x + 4

Solution

Minimum (- 1, 3)

Solution steps

f^{'} (x) = 2 x + 2

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

x^{2} + 2 x + 4 : 3

Minimum (- 1, 3)

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extreme f(x)=3x^2+6x extreme points

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+2x+4 ?
The extreme f(x)=x^2+2x+4 is Minimum(-1,3)