What is the extreme f(x)=4x^3-9x ?

The extreme f(x)=4x^3-9x is Maximum(-(sqrt(3))/2 ,3sqrt(3)),Minimum((sqrt(3))/2 ,-3sqrt(3))

Popular >

extreme f(x)=4x^3-9x

extreme points

f (x) = 4 x^{3} - 9 x

Maximum (- \frac{3}{2}, 33), Minimum (\frac{3}{2}, - 33)

Solution steps

f^{'} (x) = 12 x^{2} - 9

Find intervals:

Increasing

: - \infty < x < - \frac{3}{2},

Decreasing

: - \frac{3}{2} < x < \frac{3}{2},

Increasing

: \frac{3}{2} < x < \infty

Plug

x = - \frac{3}{2}

into

4 x^{3} - 9 x : 33

Maximum (- \frac{3}{2}, 33)

Plug

x = \frac{3}{2}

into

4 x^{3} - 9 x : - 33

Minimum (\frac{3}{2}, - 33)

Maximum (- \frac{3}{2}, 33), Minimum (\frac{3}{2}, - 33)

f (x) = \frac{∣ x ∣}{2 - x}

f (x, y) = 4 x y e^{y - x}

f (x) = 3 x^{2} + 6 x

f (x) = 3 x + 3 y

f (x, y) = 2 x^{3} y^{2} + \frac{5}{x} - \frac{1}{y} + 4

What is the extreme f(x)=4x^3-9x ?
The extreme f(x)=4x^3-9x is Maximum(-(sqrt(3))/2 ,3sqrt(3)),Minimum((sqrt(3))/2 ,-3sqrt(3))