What is the range of f(x)=1+(8+x)^{1/2} ?

The range of f(x)=1+(8+x)^{1/2} is f(x)>= 1

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range of f(x)=1+(8+x)^{1/2}

range

f (x) = 1 + (8 + x)^{\frac{1}{2}}

f (x) \geq 1

Interval Notation

[1, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 1

f (x) \geq 1

f (x) = 3 x + \frac{9}{x}

f (x) = x 16 - x^{2}

f (x) = x + 6

- 3 x + 2 y = 20

(1, 5), (1, - 4)

What is the range of f(x)=1+(8+x)^{1/2} ?
The range of f(x)=1+(8+x)^{1/2} is f(x)>= 1