What is the extreme f(x,y,z)=8x+8y+4z=5 ?

The extreme f(x,y,z)=8x+8y+4z=5 is None

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extreme f(x,y,z)=8x+8y+4z=5

extreme points

f (x, y, z) = 8 x + 8 y + 4 z = 5

None

Solution steps

Find the critical points:

None

5

has no critical points, therefore there are no extreme points

None

f (x) = x^{3} - 6 x^{2} + 9 x + 9

f (x, y) = 2 x + 4 y - 5

- 2 x^{2} + 4 x + 3

f (x) = \frac{x ^{2}}{( x - 1 )}

f (x) = - x^{3} + 3 x^{2} + 9 x + 10

What is the extreme f(x,y,z)=8x+8y+4z=5 ?
The extreme f(x,y,z)=8x+8y+4z=5 is None