What is the extreme f(x)=24x^3-3x^4=x^3(24-3x) ?

The extreme f(x)=24x^3-3x^4=x^3(24-3x) is Saddle(0,0),Maximum(6,1296)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=24x^3-3x^4=x^3(24-3x)

extreme points

f (x) = 24 x^{3} - 3 x^{4} = x^{3} (24 - 3 x)

Saddle (0, 0), Maximum (6, 1296)

Solution steps

f^{'} (x) = - 12 x^{2} (x - 6)

Find intervals:

Increasing

: - \infty < x < 0,

Increasing

: 0 < x < 6,

Decreasing

: 6 < x < \infty

Plug

x = 0

into

x^{3} (24 - 3 x) : 0

Saddle (0, 0)

Plug

x = 6

into

x^{3} (24 - 3 x) : 1296

Maximum (6, 1296)

Saddle (0, 0), Maximum (6, 1296)

f (x) = ∣ sin (x) ∣, (- π, π)

f (x) = \frac{x ^{2} - 63}{x - 8}

2 y^{2} + 2 x y + x^{2} + 2 y - 2 x + 1

f (x) = x^{2} + y^{4} + 2 x y

(x^{2} - 3) e^{x}

What is the extreme f(x)=24x^3-3x^4=x^3(24-3x) ?
The extreme f(x)=24x^3-3x^4=x^3(24-3x) is Saddle(0,0),Maximum(6,1296)