What is the extreme f(x,y)=-y^2+xy-x^3+y+3 ?

The extreme f(x,y)=-y^2+xy-x^3+y+3 is Saddle(-1/3 , 1/3),Maximum(1/2 , 3/4)

Popular >

extreme f(x,y)=-y^2+xy-x^3+y+3

extreme points

f (x, y) = - y^{2} + x y - x^{3} + y + 3

Saddle (- \frac{1}{3}, \frac{1}{3}), Maximum (\frac{1}{2}, \frac{3}{4})

Solution steps

Find the critical points:

(- \frac{1}{3}, \frac{1}{3}), (\frac{1}{2}, \frac{3}{4})

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = 12 x - 1

Check the sign of at each critical point

Check critical point

(- \frac{1}{3}, \frac{1}{3}) :

Saddle

Check critical point

(\frac{1}{2}, \frac{3}{4}) :

Maximum

Saddle (- \frac{1}{3}, \frac{1}{3}), Maximum (\frac{1}{2}, \frac{3}{4})

f (x, y) = 2 x^{2} + 3 y^{2} + 2 x y + 10 x - 20 y

f (x, y) = 48 x y - 32 x^{3} - 24 y^{2}

f (x, y) = x^{2} + x y + y^{2} - 34 y + 385

f (x, y) = 5 - 2 x + 4 y - x^{2} - 4 y^{2}

f (x) = x - 2 x

What is the extreme f(x,y)=-y^2+xy-x^3+y+3 ?
The extreme f(x,y)=-y^2+xy-x^3+y+3 is Saddle(-1/3 , 1/3),Maximum(1/2 , 3/4)