What is the extreme f(x)=x^3+3x^2-9x+7 ?

The extreme f(x)=x^3+3x^2-9x+7 is Maximum(-3,34),Minimum(1,2)

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extreme f(x)=x^3+3x^2-9x+7

extreme points

f (x) = x^{3} + 3 x^{2} - 9 x + 7

Maximum (- 3, 34), Minimum (1, 2)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 3

into

x^{3} + 3 x^{2} - 9 x + 7 : 34

Maximum (- 3, 34)

Plug

x = 1

into

x^{3} + 3 x^{2} - 9 x + 7 : 2

Minimum (1, 2)

Maximum (- 3, 34), Minimum (1, 2)

f (x) = 2 x^{3} + 9 x^{2} - 24 x + 5

f (x) = x^{2} (x - 4)^{2}

p (x) = e^{x - 3} + e^{- x}

f (x, y) = x^{2} - 2 y + y

f (x, y) = 4 x^{2} + 8 y^{2}

What is the extreme f(x)=x^3+3x^2-9x+7 ?
The extreme f(x)=x^3+3x^2-9x+7 is Maximum(-3,34),Minimum(1,2)