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Popular >

extreme x^3-6x^2+8

Solution

extreme points

x^{3} - 6 x^{2} + 8

Solution

Maximum (0, 8), Minimum (4, - 24)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 0

into

x^{3} - 6 x^{2} + 8 : 8

Maximum (0, 8)

Plug

x = 4

into

x^{3} - 6 x^{2} + 8 : - 24

Minimum (4, - 24)

Maximum (0, 8), Minimum (4, - 24)

Popular Examples

extreme f(x)=x^2-8x+7 extreme points

f (x) = x^{2} - 8 x + 7

extreme f(x)=(x-5)/(x^2-6x+9)extreme points

f (x) = \frac{x - 5}{x ^{2} - 6 x + 9}

extreme y=x^3-12x-5 extreme points

y = x^{3} - 12 x - 5

extreme y=x^3-12x+8 extreme points

y = x^{3} - 12 x + 8

extreme (x^2)/(x+3)extreme points

\frac{x ^{2}}{x + 3}

Frequently Asked Questions (FAQ)

What is the extreme x^3-6x^2+8 ?
The extreme x^3-6x^2+8 is Maximum(0,8),Minimum(4,-24)