What is the extreme f(x)= 1/3 x^3-x^2-3x+5 ?

The extreme f(x)= 1/3 x^3-x^2-3x+5 is Maximum(-1, 20/3),Minimum(3,-4)

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extreme f(x)= 1/3 x^3-x^2-3x+5

extreme points

f (x) = \frac{1}{3} x^{3} - x^{2} - 3 x + 5

Maximum (- 1, \frac{20}{3}), Minimum (3, - 4)

Solution steps

f^{'} (x) = x^{2} - 2 x - 3

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 1

into

\frac{1}{3} x^{3} - x^{2} - 3 x + 5 : \frac{20}{3}

Maximum (- 1, \frac{20}{3})

Plug

x = 3

into

\frac{1}{3} x^{3} - x^{2} - 3 x + 5 : - 4

Minimum (3, - 4)

Maximum (- 1, \frac{20}{3}), Minimum (3, - 4)

f (x, y) = x^{3} + y^{3} - 27 x y

f (x) = x^{3} + x^{2} - 5 x - 5

f (x, y) = 5 x^{2} + 3 x y + e^{x y}

f (x) = x^{3} + 2 x^{2} + b

f (x) = 0.01 x^{3} + 0.45 x^{2} + 2.43 x + 300

What is the extreme f(x)= 1/3 x^3-x^2-3x+5 ?
The extreme f(x)= 1/3 x^3-x^2-3x+5 is Maximum(-1, 20/3),Minimum(3,-4)