What is the extreme f(x)=0.01x^3+0.45x^2+2.43x+300 ?

The extreme f(x)=0.01x^3+0.45x^2+2.43x+300 is Maximum(-27,365.61),Minimum(-3,296.49)

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extreme f(x)=0.01x^3+0.45x^2+2.43x+300

extreme points

f (x) = 0.01 x^{3} + 0.45 x^{2} + 2.43 x + 300

Maximum (- 27, 365.61), Minimum (- 3, 296.49)

Solution steps

f^{'} (x) = 0.03 x^{2} + 0.9 x + 2.43

Find intervals:

Increasing

: - \infty < x < - 144 - 15,

Decreasing

: - 144 - 15 < x < 144 - 15,

Increasing

: 144 - 15 < x < \infty

Plug

x = - 27

into

0.01 x^{3} + 0.45 x^{2} + 2.43 x + 300 : 365.61

Maximum (- 27, 365.61)

Plug

x = - 3

into

0.01 x^{3} + 0.45 x^{2} + 2.43 x + 300 : 296.49

Minimum (- 3, 296.49)

Maximum (- 27, 365.61), Minimum (- 3, 296.49)

f (x) = \frac{1}{9} \cdot (\frac{x ^{3}}{x + 2})

f (x) = x^{3} - 5 x^{2} + 3 x + 10, - 2 \leq x \leq 4

f (x, y) = 2 x^{2} + y^{2} - 4 x - 2 y + 3

f (x, y) = x^{4} - 2 x^{2} + y^{3} - 3 y

ln (x^{4} + 27)

What is the extreme f(x)=0.01x^3+0.45x^2+2.43x+300 ?
The extreme f(x)=0.01x^3+0.45x^2+2.43x+300 is Maximum(-27,365.61),Minimum(-3,296.49)