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Popular >

extreme f(x)=-x^2+2x+5

Solution

extreme points

f (x) = - x^{2} + 2 x + 5

Solution

Maximum (1, 6)

Solution steps

f^{'} (x) = - 2 x + 2

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = 1

into

- x^{2} + 2 x + 5 : 6

Maximum (1, 6)

Popular Examples

extreme f(x)=3x^3-x^2+4x-2 extreme points

f (x) = 3 x^{3} - x^{2} + 4 x - 2

extreme f(x,y)=-96*x+2*x^3+6*x*y^2-3*y^3 extreme points

f (x, y) = - 96 \cdot x + 2 \cdot x^{3} + 6 \cdot x \cdot y^{2} - 3 \cdot y^{3}

extreme y=x^3-3x^2-9x+5 extreme points

y = x^{3} - 3 x^{2} - 9 x + 5

extreme f(x)=x^2(x-2)^3(x+2)^3 extreme points

f (x) = x^{2} (x - 2)^{3} (x + 2)^{3}

extreme f(x,y)=(xy)/((x^2-y^2)^2)extreme points

f (x, y) = \frac{x y}{( x ^{2} - y ^{2} ) ^{2}}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-x^2+2x+5 ?
The extreme f(x)=-x^2+2x+5 is Maximum(1,6)