What is the extreme y=x^3-3x^2-9x+5 ?

The extreme y=x^3-3x^2-9x+5 is Maximum(-1,10),Minimum(3,-22)

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extreme y=x^3-3x^2-9x+5

extreme points

y = x^{3} - 3 x^{2} - 9 x + 5

Maximum (- 1, 10), Minimum (3, - 22)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x^{2} - 9 x + 5 : 10

Maximum (- 1, 10)

Plug

x = 3

into

x^{3} - 3 x^{2} - 9 x + 5 : - 22

Minimum (3, - 22)

Maximum (- 1, 10), Minimum (3, - 22)

f (x) = x^{2} (x - 2)^{3} (x + 2)^{3}

f (x, y) = \frac{x y}{( x ^{2} - y ^{2} ) ^{2}}

f (x) = 2 x^{5} - 6 x^{4}

f (x) = x^{2} - 10 x + 24

f (x) = 2 x + \frac{300000}{x}, 1 \leq x \leq 300

What is the extreme y=x^3-3x^2-9x+5 ?
The extreme y=x^3-3x^2-9x+5 is Maximum(-1,10),Minimum(3,-22)