What is the domain of f(x)=(x^2)/(sqrt(25-x^2)) ?

The domain of f(x)=(x^2)/(sqrt(25-x^2)) is -5<x<5

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domain of f(x)=(x^2)/(sqrt(25-x^2))

domain

f (x) = \frac{x ^{2}}{25 - x ^{2}}

- 5 < x < 5

Interval Notation

(- 5, 5)

Solution steps

Find non-negative values for radicals:

- 5 \leq x \leq 5

Find undefined (singularity) points:

x = 5, x = - 5

Combine real regions and undefined points for final function domain

- 5 < x < 5

f (x) = \frac{9 x}{x + 9}

f (x) = x^{2} + 5 x - 6

\frac{x ^{2} + 3}{x ^{2} - 2 x - 3}

f (x) = - 2 x + 4

f (x) = \frac{7}{x - 3}

What is the domain of f(x)=(x^2)/(sqrt(25-x^2)) ?
The domain of f(x)=(x^2)/(sqrt(25-x^2)) is -5<x<5