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Popular >

extreme f(x)=2x^2+3x-5

Solution

extreme points

f (x) = 2 x^{2} + 3 x - 5

Solution

Minimum (- \frac{3}{4}, - \frac{49}{8})

Solution steps

f^{'} (x) = 4 x + 3

Find intervals:

Decreasing

: - \infty < x < - \frac{3}{4},

Increasing

: - \frac{3}{4} < x < \infty

Plug

x = - \frac{3}{4}

into

2 x^{2} + 3 x - 5 : - \frac{49}{8}

Minimum (- \frac{3}{4}, - \frac{49}{8})

Popular Examples

extreme f(x)=x^3-12x-10 extreme points

f (x) = x^{3} - 12 x - 10

extreme g(x)=x^2-6x-12 extreme points

g (x) = x^{2} - 6 x - 12

extreme f(x)=-6x+5y extreme points

f (x) = - 6 x + 5 y

extreme f(x)=-1/2 x^4+2x^3+40x^2-13 extreme points

f (x) = - \frac{1}{2} x^{4} + 2 x^{3} + 40 x^{2} - 13

extreme f(x)=3x-2x^2-4/3 x^3 extreme points

f (x) = 3 x - 2 x^{2} - \frac{4}{3} x^{3}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2+3x-5 ?
The extreme f(x)=2x^2+3x-5 is Minimum(-3/4 ,-49/8)