What is the extreme f(x)=x^3-12x-10 ?

The extreme f(x)=x^3-12x-10 is Maximum(-2,6),Minimum(2,-26)

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extreme f(x)=x^3-12x-10

extreme points

f (x) = x^{3} - 12 x - 10

Maximum (- 2, 6), Minimum (2, - 26)

Solution steps

f^{'} (x) = 3 x^{2} - 12

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

x^{3} - 12 x - 10 : 6

Maximum (- 2, 6)

Plug

x = 2

into

x^{3} - 12 x - 10 : - 26

Minimum (2, - 26)

Maximum (- 2, 6), Minimum (2, - 26)

g (x) = x^{2} - 6 x - 12

f (x) = - 6 x + 5 y

f (x) = - \frac{1}{2} x^{4} + 2 x^{3} + 40 x^{2} - 13

f (x) = 3 x - 2 x^{2} - \frac{4}{3} x^{3}

f (x) = (x^{3} - 5 x^{2} + 11 x - 11) e^{x}

What is the extreme f(x)=x^3-12x-10 ?
The extreme f(x)=x^3-12x-10 is Maximum(-2,6),Minimum(2,-26)