en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-x^2+6x-4

Solution

extreme points

f (x) = - x^{2} + 6 x - 4

Solution

Maximum (3, 5)

Solution steps

f^{'} (x) = - 2 x + 6

Find intervals:

Increasing

: - \infty < x < 3,

Decreasing

: 3 < x < \infty

Plug

x = 3

into

- x^{2} + 6 x - 4 : 5

Maximum (3, 5)

Popular Examples

extreme f(x)=x^3-12x+11 extreme points

f (x) = x^{3} - 12 x + 11

extreme f(x)=(4-2)(4-6)^3+8 extreme points

f (x) = (4 - 2) (4 - 6)^{3} + 8

extreme y=(x^2-4)/(x^2+4)extreme points

y = \frac{x ^{2} - 4}{x ^{2} + 4}

extreme f(x)=x^2-12x+6 extreme points

f (x) = x^{2} - 12 x + 6

extreme f(x)=x^2-12x+7 extreme points

f (x) = x^{2} - 12 x + 7

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-x^2+6x-4 ?
The extreme f(x)=-x^2+6x-4 is Maximum(3,5)