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Popular >

extreme y=(x^2-4)/(x^2+4)

Solution

extreme points

y = \frac{x ^{2} - 4}{x ^{2} + 4}

Solution

Minimum (0, - 1)

Solution steps

f^{'} (x) = \frac{16 x}{( x ^{2} + 4 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

\frac{x ^{2} - 4}{x ^{2} + 4} : - 1

Minimum (0, - 1)

Popular Examples

extreme f(x)=x^2-12x+6 extreme points

f (x) = x^{2} - 12 x + 6

extreme f(x)=x^2-12x+7 extreme points

f (x) = x^{2} - 12 x + 7

extreme f(x)=-x^3+3x^2+5 extreme points

f (x) = - x^{3} + 3 x^{2} + 5

extreme x^5-5x^3-20x-2 extreme points

x^{5} - 5 x^{3} - 20 x - 2

extreme f(x)=(1+xy)(x+y)extreme points

f (x) = (1 + x y) (x + y)

Frequently Asked Questions (FAQ)

What is the extreme y=(x^2-4)/(x^2+4) ?
The extreme y=(x^2-4)/(x^2+4) is Minimum(0,-1)