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Popular >

extreme (x-2)^2+1

Solution

extreme points

(x - 2)^{2} + 1

Solution

Minimum (2, 1)

Solution steps

f^{'} (x) = 2 x - 4

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

(x - 2)^{2} + 1 : 1

Minimum (2, 1)

Popular Examples

extreme f(x,y)=16xy-x^3-8y^2 extreme points

f (x, y) = 16 x y - x^{3} - 8 y^{2}

extreme f(x,y)=x^3-3x^2y+y^2+2y-3 extreme points

f (x, y) = x^{3} - 3 x^{2} y + y^{2} + 2 y - 3

extreme f(x)=x^3+y^3-9xy extreme points

f (x) = x^{3} + y^{3} - 9 x y

extreme f(x)={4-2x,x<= 1}extreme points

f (x) = {4 - 2 x, x \leq 1}

extreme f(x,y)=ln(x^2-4x+2y^2-16y+16)extreme points

f (x, y) = ln (x^{2} - 4 x + 2 y^{2} - 16 y + 16)

Frequently Asked Questions (FAQ)

What is the extreme (x-2)^2+1 ?
The extreme (x-2)^2+1 is Minimum(2,1)