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Popular >

extreme g(x)= 3/2 x^2+6x+4

Solution

extreme points

g (x) = \frac{3}{2} x^{2} + 6 x + 4

Solution

Minimum (- 2, - 2)

Solution steps

f^{'} (x) = 3 x + 6

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 2

into

\frac{3}{2} x^{2} + 6 x + 4 : - 2

Minimum (- 2, - 2)

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Frequently Asked Questions (FAQ)

What is the extreme g(x)= 3/2 x^2+6x+4 ?
The extreme g(x)= 3/2 x^2+6x+4 is Minimum(-2,-2)