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Popular >

extreme f(x)=x^2+5

Solution

extreme points

f (x) = x^{2} + 5

Solution

Minimum (0, 5)

Solution steps

f^{'} (x) = 2 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{2} + 5 : 5

Minimum (0, 5)

Popular Examples

extreme f(x)=4x^2-16x+16 extreme points

f (x) = 4 x^{2} - 16 x + 16

extreme f(x)= 4/(4-x)extreme points

f (x) = \frac{4}{4 - x}

extreme f(x)=((x-6))/(x^2)extreme points

f (x) = \frac{( x - 6 )}{x ^{2}}

extreme f(x)=(x-2)^3+8 extreme points

f (x) = (x - 2)^{3} + 8

extreme f(x)=x^{5/3}-2x^{2/3}extreme points

f (x) = x^{\frac{5}{3}} - 2 x^{\frac{2}{3}}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+5 ?
The extreme f(x)=x^2+5 is Minimum(0,5)