What is the extreme f(x)=x^4-50x^2+6 ?

The extreme f(x)=x^4-50x^2+6 is Minimum(-5,-619),Maximum(0,6),Minimum(5,-619)

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extreme f(x)=x^4-50x^2+6

extreme points

f (x) = x^{4} - 50 x^{2} + 6

Minimum (- 5, - 619), Maximum (0, 6), Minimum (5, - 619)

Solution steps

f^{'} (x) = 4 x^{3} - 100 x

Find intervals:

Decreasing

: - \infty < x < - 5,

Increasing

: - 5 < x < 0,

Decreasing

: 0 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = - 5

into

x^{4} - 50 x^{2} + 6 : - 619

Minimum (- 5, - 619)

Plug

x = 0

into

x^{4} - 50 x^{2} + 6 : 6

Maximum (0, 6)

Plug

x = 5

into

x^{4} - 50 x^{2} + 6 : - 619

Minimum (5, - 619)

Minimum (- 5, - 619), Maximum (0, 6), Minimum (5, - 619)

f (x, y) = 4 (x - y) - x^{2} - y^{2}

\frac{3 x ^{2}}{x ^{2} - 25}

f (x) = - x^{3} - x^{2} + 5 x, - 2 \leq x \leq 2

f (x) = - x^{2} + 12 x - 32

f (x) = 3 x^{2} - 12 x + 5, 0 \leq x \leq 3

What is the extreme f(x)=x^4-50x^2+6 ?
The extreme f(x)=x^4-50x^2+6 is Minimum(-5,-619),Maximum(0,6),Minimum(5,-619)