What is the extreme f(x)=x^3-12x^2+45x ?

The extreme f(x)=x^3-12x^2+45x is Maximum(3,54),Minimum(5,50)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3-12x^2+45x

extreme points

f (x) = x^{3} - 12 x^{2} + 45 x

Maximum (3, 54), Minimum (5, 50)

Solution steps

f^{'} (x) = 3 x^{2} - 24 x + 45

Find intervals:

Increasing

: - \infty < x < 3,

Decreasing

: 3 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = 3

into

x^{3} - 12 x^{2} + 45 x : 54

Maximum (3, 54)

Plug

x = 5

into

x^{3} - 12 x^{2} + 45 x : 50

Minimum (5, 50)

Maximum (3, 54), Minimum (5, 50)

f (x, y) = (x^{2} - y^{2})

f (x) = - 3 x^{3} + 5 x^{2}

f (x) = t 4 - t

x^{2} + \frac{1}{x}

f (x) = x^{3} - x^{2} - x + 8, - 1 \leq x \leq 0

What is the extreme f(x)=x^3-12x^2+45x ?
The extreme f(x)=x^3-12x^2+45x is Maximum(3,54),Minimum(5,50)