What is the extreme x^2+1/x ?

The extreme x^2+1/x is Minimum(1/(\sqrt[3]{2)}, 1/(2^{2/3)}+\sqrt[3]{2})

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extreme x^2+1/x

extreme points

x^{2} + \frac{1}{x}

Solution steps

f^{'} (x) = 2 x - \frac{1}{x ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

Increasing

Plug

into

f (x) = x^{3} - x^{2} - x + 8, - 1 \leq x \leq 0

f (x) = \frac{12 x}{9 + x ^{2}}

f (x, y) = 4 - 2 x + 4 y - x^{2} - 4 y^{2}

f (x) = 2 x^{\frac{5}{3}} - 5 x^{\frac{4}{3}}

f (x) = 2 (3 x + 2)^{2} - 3 x^{4}

What is the extreme x^2+1/x ?
The extreme x^2+1/x is Minimum(1/(\sqrt[3]{2)}, 1/(2^{2/3)}+\sqrt[3]{2})