What is the extreme f(x)=2x^{5/3}-5x^{4/3} ?

The extreme f(x)=2x^{5/3}-5x^{4/3} is Maximum(0,0),Minimum(8,-16)

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extreme f(x)=2x^{5/3}-5x^{4/3}

extreme points

f (x) = 2 x^{\frac{5}{3}} - 5 x^{\frac{4}{3}}

Maximum (0, 0), Minimum (8, - 16)

Solution steps

f^{'} (x) = \frac{10 x ^{\frac{2}{3}} - 20 x ^{\frac{1}{3}}}{3}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 8,

Increasing

: 8 < x < \infty

Plug

x = 0

into

2 x^{\frac{5}{3}} - 5 x^{\frac{4}{3}} : 0

Maximum (0, 0)

Plug

x = 8

into

2 x^{\frac{5}{3}} - 5 x^{\frac{4}{3}} : - 16

Minimum (8, - 16)

Maximum (0, 0), Minimum (8, - 16)

f (x) = 2 (3 x + 2)^{2} - 3 x^{4}

y = x (x + 4)^{3}

f (x) = \frac{4 x}{x ^{2} - 49}

f (x) = x^{3} - 6 x^{2} + 8, - 1 \leq x \leq 6

f (x, y) = x^{2} - x y + y^{2} + 5

What is the extreme f(x)=2x^{5/3}-5x^{4/3} ?
The extreme f(x)=2x^{5/3}-5x^{4/3} is Maximum(0,0),Minimum(8,-16)