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Popular >

extreme f(x)=ln(27+x^3)

Solution

extreme points

f (x) = ln (27 + x^{3})

Solution

Saddle (0, 3 ln (3))

Solution steps

f^{'} (x) = \frac{3 x ^{2}}{27 + x ^{3}}

Find intervals:

Increasing

: - 3 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

ln (27 + x^{3}) : 3 ln (3)

Saddle (0, 3 ln (3))

Popular Examples

extreme f(x)=x^3-9x^2+27x-3 extreme points

f (x) = x^{3} - 9 x^{2} + 27 x - 3

extreme f(x,y)=y^2+xy+3x+2y+5 extreme points

f (x, y) = y^{2} + x y + 3 x + 2 y + 5

solvefor E,E=(IR)/I solve for

E, E = \frac{I R}{I}

extreme f(x)=3+8x^3-y^3-12xy extreme points

f (x) = 3 + 8 x^{3} - y^{3} - 12 x y

extreme y(x,t)=x(3t-9)extreme points

y (x, t) = x (3 t - 9)

Frequently Asked Questions (FAQ)

What is the extreme f(x)=ln(27+x^3) ?
The extreme f(x)=ln(27+x^3) is Saddle(0,3ln(3))