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Popular >

extreme f(x)=x^2+8x+16

Solution

extreme points

f (x) = x^{2} + 8 x + 16

Solution

Minimum (- 4, 0)

Solution steps

f^{'} (x) = 2 x + 8

Find intervals:

Decreasing

: - \infty < x < - 4,

Increasing

: - 4 < x < \infty

Plug

x = - 4

into

x^{2} + 8 x + 16 : 0

Minimum (- 4, 0)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+8x+16 ?
The extreme f(x)=x^2+8x+16 is Minimum(-4,0)