What is the extreme f(x)=-cos(x) ?

The extreme f(x)=-cos(x) is Minimum(2pin,-1),Maximum(pi+2pin,1)

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extreme f(x)=-cos(x)

extreme points

f (x) = - cos (x)

Minimum (2 πn, - 1), Maximum (π + 2 πn, 1)

Solution steps

Find the critical points:

x = 2 πn, x = π + 2 πn

Domain of

- cos (x) : - \infty < x < \infty

Find intervals:

Increasing

: 2 πn < x < π + 2 πn,

Decreasing

: π + 2 πn < x < 2 π + 2 πn

Plug the extreme point

x = 2 πn

into

- cos (x) \Rightarrow y = - 1

Minimum (2 πn, - 1)

Plug the extreme point

x = π + 2 πn

into

- cos (x) \Rightarrow y = 1

Maximum (π + 2 πn, 1)

Minimum (2 πn, - 1), Maximum (π + 2 πn, 1)

f (x) = 2 x^{3} + 5 x^{2} - 25 x

f (x, y) = 1 - 4 x^{2} - y^{2}

x e^{2 x}

f (x) = x^{2} - 3 x - 4

f (x) = 3 x^{\frac{2}{3}} + 2 x - 1

What is the extreme f(x)=-cos(x) ?
The extreme f(x)=-cos(x) is Minimum(2pin,-1),Maximum(pi+2pin,1)