What is the extreme f(x)=-x-(64)/x ?

The extreme f(x)=-x-(64)/x is Minimum(-8,16),Maximum(8,-16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-x-(64)/x

extreme points

f (x) = - x - \frac{64}{x}

Minimum (- 8, 16), Maximum (8, - 16)

Solution steps

f^{'} (x) = - 1 + \frac{64}{x ^{2}}

Find intervals:

Decreasing

: - \infty < x < - 8,

Increasing

: - 8 < x < 0,

Increasing

: 0 < x < 8,

Decreasing

: 8 < x < \infty

Plug

x = - 8

into

- x - \frac{64}{x} : 16

Minimum (- 8, 16)

Plug

x = 8

into

- x - \frac{64}{x} : - 16

Maximum (8, - 16)

Minimum (- 8, 16), Maximum (8, - 16)

f (x) = \frac{1}{3} x^{5} - \frac{5}{2} x^{2} + 6 x - 8

f (x) = e^{x} (8 - x^{2})

\frac{2 x ^{2}}{x ^{2} - 1}

f (x, y) = 2 x - x^{2} + 2 y^{2} - y^{4}

f (x) = x^{3} - 9 x^{2} + 24

What is the extreme f(x)=-x-(64)/x ?
The extreme f(x)=-x-(64)/x is Minimum(-8,16),Maximum(8,-16)