What is the extreme f(x,y)=-2x^2+5xy-3y^2+x+y ?

The extreme f(x,y)=-2x^2+5xy-3y^2+x+y is Saddle(-11,-9)

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extreme f(x,y)=-2x^2+5xy-3y^2+x+y

extreme points

f (x, y) = - 2 x^{2} + 5 x y - 3 y^{2} + x + y

Saddle (- 11, - 9)

Solution steps

Find the critical points:

(- 11, - 9)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 6

D (x, y) = - 1

Check the sign of at each critical point

Check critical point

(- 11, - 9) :

Saddle

Saddle (- 11, - 9)

f (x) = \frac{5 x - 2}{x ^{2} - 10 x + 25}

p (a, c) = a + 5 + c

f (x) = \frac{( e ^{x^{2}} + e ^{2 - x^{2}} )}{5}

f (x, y) = 4 y^{2} - 6 x y

f (x, y) = x^{2} + 6 x y + 12 y^{2} - 6 x + 10 y - 2

What is the extreme f(x,y)=-2x^2+5xy-3y^2+x+y ?
The extreme f(x,y)=-2x^2+5xy-3y^2+x+y is Saddle(-11,-9)