What is the extreme f(x)=x^3+3x^2-9x+2 ?

The extreme f(x)=x^3+3x^2-9x+2 is Maximum(-3,29),Minimum(1,-3)

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extreme f(x)=x^3+3x^2-9x+2

extreme points

f (x) = x^{3} + 3 x^{2} - 9 x + 2

Maximum (- 3, 29), Minimum (1, - 3)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 3

into

x^{3} + 3 x^{2} - 9 x + 2 : 29

Maximum (- 3, 29)

Plug

x = 1

into

x^{3} + 3 x^{2} - 9 x + 2 : - 3

Minimum (1, - 3)

Maximum (- 3, 29), Minimum (1, - 3)

f (x) = 2 x^{3} + 6 x^{2} - 5

f (x) = 3 x^{2} - 5 x - 4

f (x) = (x^{2} - x)^{\frac{2}{3}}

f (x) = x + 1

f (x) = x e^{- 5 x^{2}}

What is the extreme f(x)=x^3+3x^2-9x+2 ?
The extreme f(x)=x^3+3x^2-9x+2 is Maximum(-3,29),Minimum(1,-3)