What is the extreme (-3x+48)/((x-120)^9) ?

The extreme (-3x+48)/((x-120)^9) is None

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extreme (-3x+48)/((x-120)^9)

extreme points

\frac{- 3 x + 48}{( x - 120 ) ^{9}}

None

Solution steps

Find the critical points:

x = 3

Domain of

\frac{- 3 x + 48}{( x - 120 ) ^{9}} : x < 120 or x > 120

Find intervals:

Constant

: - \infty < x < 3,

Increasing

: 3 < x < 120,

Increasing

: 120 < x < \infty

None

f (x, y) = x^{2} + x y + y^{2} + x + a y

e^{x}

f (x) = x^{2} + y^{2} + 5

\frac{24}{r} + 2 π r^{2}

\frac{d}{d x} (9 x^{3} y^{5})

What is the extreme (-3x+48)/((x-120)^9) ?
The extreme (-3x+48)/((x-120)^9) is None