What is the extreme (24)/r+2pir^2 ?

The extreme (24)/r+2pir^2 is Minimum(\sqrt[3]{6/pi},4*6^{2/3}\sqrt[3]{pi}+2pi(6/pi)^{2/3})

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extreme (24)/r+2pir^2

extreme points

\frac{24}{r} + 2 π r^{2}

Solution steps

f^{'} (r) = - \frac{24}{r ^{2}} + 4 π r

Find intervals:

Decreasing

: - \infty < r < 0,

Decreasing

Increasing

Plug

into

\frac{d}{d x} (9 x^{3} y^{5})

f (x) = 6 y^{2} + 4 x^{2} - 12 x y - 4 y

f (x) = x^{3} + 4 x^{2} - 3 x + 6

f (x, y) = x^{3} + y^{3} + 2 x^{2} + 4 y^{2} + 6

f (x) = 3 x^{2} - 18 x + 23

What is the extreme (24)/r+2pir^2 ?
The extreme (24)/r+2pir^2 is Minimum(\sqrt[3]{6/pi},4*6^{2/3}\sqrt[3]{pi}+2pi(6/pi)^{2/3})