What is the extreme f(x)=x^3+4x^2-3x+6 ?

The extreme f(x)=x^3+4x^2-3x+6 is Maximum(-3,24),Minimum(1/3 , 148/27)

Popular >

extreme f(x)=x^3+4x^2-3x+6

extreme points

f (x) = x^{3} + 4 x^{2} - 3 x + 6

Maximum (- 3, 24), Minimum (\frac{1}{3}, \frac{148}{27})

Solution steps

f^{'} (x) = 3 x^{2} + 8 x - 3

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < \frac{1}{3},

Increasing

: \frac{1}{3} < x < \infty

Plug

x = - 3

into

x^{3} + 4 x^{2} - 3 x + 6 : 24

Maximum (- 3, 24)

Plug

x = \frac{1}{3}

into

x^{3} + 4 x^{2} - 3 x + 6 : \frac{148}{27}

Minimum (\frac{1}{3}, \frac{148}{27})

Maximum (- 3, 24), Minimum (\frac{1}{3}, \frac{148}{27})

f (x, y) = x^{3} + y^{3} + 2 x^{2} + 4 y^{2} + 6

f (x) = 3 x^{2} - 18 x + 23

f (x, y) = 5 + 3 x^{2} + 3 y^{2} + 2 y^{3} + x^{3}

f (x) = 4 + x^{3} + y^{3} - 3 x y

f (x) = 3 x^{3} - 9 x + 3

What is the extreme f(x)=x^3+4x^2-3x+6 ?
The extreme f(x)=x^3+4x^2-3x+6 is Maximum(-3,24),Minimum(1/3 , 148/27)