What is the extreme f(x)=3x^3-9x+3 ?

The extreme f(x)=3x^3-9x+3 is Maximum(-1,9),Minimum(1,-3)

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extreme f(x)=3x^3-9x+3

extreme points

f (x) = 3 x^{3} - 9 x + 3

Maximum (- 1, 9), Minimum (1, - 3)

Solution steps

f^{'} (x) = 9 x^{2} - 9

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

3 x^{3} - 9 x + 3 : 9

Maximum (- 1, 9)

Plug

x = 1

into

3 x^{3} - 9 x + 3 : - 3

Minimum (1, - 3)

Maximum (- 1, 9), Minimum (1, - 3)

y = x^{3} + x^{2} - x + 8

f (x) = 3 x 8 - x^{2}

f (x) = e^{(x^{2} - 7 x - 1)}

x^{\frac{2}{3}} - 6 x^{- \frac{1}{3}}

f (x, y) = \frac{4}{x + y}

What is the extreme f(x)=3x^3-9x+3 ?
The extreme f(x)=3x^3-9x+3 is Maximum(-1,9),Minimum(1,-3)