What is the extreme y=x^3+x^2-x+8 ?

The extreme y=x^3+x^2-x+8 is Maximum(-1,9),Minimum(1/3 , 211/27)

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extreme y=x^3+x^2-x+8

extreme points

y = x^{3} + x^{2} - x + 8

Maximum (- 1, 9), Minimum (\frac{1}{3}, \frac{211}{27})

Solution steps

f^{'} (x) = 3 x^{2} + 2 x - 1

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < \frac{1}{3},

Increasing

: \frac{1}{3} < x < \infty

Plug

x = - 1

into

x^{3} + x^{2} - x + 8 : 9

Maximum (- 1, 9)

Plug

x = \frac{1}{3}

into

x^{3} + x^{2} - x + 8 : \frac{211}{27}

Minimum (\frac{1}{3}, \frac{211}{27})

Maximum (- 1, 9), Minimum (\frac{1}{3}, \frac{211}{27})

f (x) = 3 x 8 - x^{2}

f (x) = e^{(x^{2} - 7 x - 1)}

x^{\frac{2}{3}} - 6 x^{- \frac{1}{3}}

f (x, y) = \frac{4}{x + y}

f (x) = 3 x^{3} - 36 x + 3

What is the extreme y=x^3+x^2-x+8 ?
The extreme y=x^3+x^2-x+8 is Maximum(-1,9),Minimum(1/3 , 211/27)