What is the perpendicular y=3x-2,(-9,5) ?

The perpendicular y=3x-2,(-9,5) is y=-1/3 x+2

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perpendicular y=3x-2,(-9,5)

perpendicular

y = 3 x - 2, (- 9, 5)

y = - \frac{1}{3} x + 2

Solution steps

Find the line

y = mx + b

perpendicular to

y = 3 x - 2

that passes through

(- 9, 5)

Find the slope of

y = 3 x - 2 : m = 3

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{3}

Find the line with slope m=

- \frac{1}{3}

and passing through

(- 9, 5) : y = - \frac{1}{3} x + 2

y = - \frac{1}{3} x + 2

f (x) = x^{2} + 2 x

f (x) = x^{5} + x^{4}

\frac{3}{4} x - 6

f (x) = \frac{1}{3 x + 7}

f (x) = 3^{x - 4}

What is the perpendicular y=3x-2,(-9,5) ?
The perpendicular y=3x-2,(-9,5) is y=-1/3 x+2